How to align columns in output from a UNIX command?
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Chapters
00:00 Question
00:38 Accepted answer (Score 36)
00:56 Answer 2 (Score 3)
01:58 Thank you
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Full question
https://superuser.com/questions/183861/h...
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Tags
#unix
#avk47
Become or hire the top 3% of the developers on Toptal https://topt.al/25cXVn
--------------------------------------------------
Music by Eric Matyas
https://www.soundimage.org
Track title: Switch On Looping
--
Chapters
00:00 Question
00:38 Accepted answer (Score 36)
00:56 Answer 2 (Score 3)
01:58 Thank you
--
Full question
https://superuser.com/questions/183861/h...
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#unix
#avk47
ACCEPTED ANSWER
Score 37
It's column
. Try for example echo -e "aaaaa bbbbbbb\ncc ddd" | column -t
.
ANSWER 2
Score 3
awk
solution that deals with stdin
Since column
is not POSIX, maybe this is:
mycolumn() (
file="${1:--}"
if [ "$file" = - ]; then
file="$(mktemp)"
cat >"${file}"
fi
awk '
FNR == 1 { if (NR == FNR) next }
NR == FNR {
for (i = 1; i <= NF; i++) {
l = length($i)
if (w[i] < l)
w[i] = l
}
next
}
{
for (i = 1; i <= NF; i++)
printf "%*s", w[i] + (i > 1 ? 1 : 0), $i
print ""
}
' "$file" "$file"
if [ "$file" = - ]; then
rm "$file"
fi
)
Test:
printf '12 1234 1
12345678 1 123
1234 123456 123456
' > file
Test commands:
mycolumn file
mycolumn <file
mycolumn - <file
Output for all:
12 1234 1
12345678 1 123
1234 123456 123456
See also: