How do I use a Bash variable (string) containing quotes in a command?
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Track title: CC O Beethoven - Piano Sonata No 3 in C
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Chapters
00:00 Question
00:27 Accepted answer (Score 80)
01:19 Answer 2 (Score 7)
01:39 Answer 3 (Score 4)
01:54 Answer 4 (Score 0)
02:25 Thank you
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Full question
https://superuser.com/questions/360966/h...
Accepted answer links:
[BashFAQ #50]: http://mywiki.wooledge.org/BashFAQ/050
Answer 2 links:
https://unix.stackexchange.com/questions...
https://stackoverflow.com/questions/7454...
Answer 4 links:
https://www.thegeekdiary.com/how-to-make.../
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
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Tags
#bash
#avk47
--
Track title: CC O Beethoven - Piano Sonata No 3 in C
--
Chapters
00:00 Question
00:27 Accepted answer (Score 80)
01:19 Answer 2 (Score 7)
01:39 Answer 3 (Score 4)
01:54 Answer 4 (Score 0)
02:25 Thank you
--
Full question
https://superuser.com/questions/360966/h...
Accepted answer links:
[BashFAQ #50]: http://mywiki.wooledge.org/BashFAQ/050
Answer 2 links:
https://unix.stackexchange.com/questions...
https://stackoverflow.com/questions/7454...
Answer 4 links:
https://www.thegeekdiary.com/how-to-make.../
--
Content licensed under CC BY-SA
https://meta.stackexchange.com/help/lice...
--
Tags
#bash
#avk47